(28/y^2-25)+1=(6/y-5)

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Solution for (28/y^2-25)+1=(6/y-5) equation: 



(28/y^2-25)+1=(6/y-5)

We move all terms to the left:

(28/y^2-25)+1-((6/y-5))=0



Domain of the equation: y^2-25)!=0

y∈R





Domain of the equation: y-5))!=0

y∈R



We get rid of parentheses

28/y^2-((6/y-5))-25+1=0

We calculate fractions

We do not support eypression: y^3

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